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40x^2-46x-14=0
a = 40; b = -46; c = -14;
Δ = b2-4ac
Δ = -462-4·40·(-14)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-66}{2*40}=\frac{-20}{80} =-1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+66}{2*40}=\frac{112}{80} =1+2/5 $
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